long haired GSD's - Page 3

You can only apply the LC x LC = all LC formula to a trait that in inherited by the simple recessive mode of inheritance. Color inheritance is a lot more complicated than that.

hi all i bought a lc from germany red sable as i loved her mother frisbee von arlett so much/ she absolute stunning dark sable,i bought her for the breed lines as u wouldnt get a normal coat out of this particular female, so i opted to take the long coatif u would like to see her its www.draycoregsd.co.uk and i have people chasing me for long coat pups regards all jeanette

i have mated lc female to male with lc gene and produced 1 lc puppy, i also mated other way round and produced 3 lc pups so i dont know what the split would be as it does vary,also if u mate sable to sable not necessary will u produce all sables as its a recessive gene so parents grandparents all have to be sable etc hope this helps regards dragon

Hi Dragon, The odds of producing or not procuding long coated puppies are as follows: LC x LC = 100% LC LC x carrier = 50% carriers, 50% LC LC x clear = 100% carriers Carrier x carrier = 25% clear, 50% carrier, 25% LC Clear x carrier =50% clear, 50% carrier Clear x clear = 100% clear These numbers are based on the odds and it's like flipping a coin 100 times. Odds are you will get 50 heads, 50 tails, but the first 10 flips could all be heads or tails. There are not normally enough puppies in one litter to assume normal coated parents do not carry the gene recessively. It is possible to breed 2 dogs, produce a litter of say 10 and not get any LC's. However, you could repeat that breeding and get LC's although the odds are against that happening. It's just the luck of the draw sometimes. Most canine genetisists think that in order to prove a dog is free of a simple recessive, it needs to produce a minimum of 5 normal puppies if bred to an effected dog, 10 normals if bred to a normal carrier and even then there is still a chance that a carrier will slip through the cracks. Now that the DNA test for the LC gene in the GSD is available, it takes all the guess work out of the equation. I've not seen a LC sable, but I imagine she is a beautiful dog. My LC was black and mahogany red, he was beautiful.

My black LC came from parents who were both all black and both standard coated but carriers of the LC gene. (The breeder was unaware that either parent was a carrier as neither dog had thrown a LC before when mated to other dogs. This was the first time he had mated the parents together.) There were 8 pups in the litter, all were solid black, and 4 were LC and the other 4 were standard coat.

That time there were more LC's than would have been expected statistically. Ya just never know...........

The stats will only be born out with a large sampling. By the way there is a simple autosomal recessive mode of inheritance and a definite succession of dominance in coat color, sable being most dominant among GSDs.

True and now that there is a DNA test for the LC gene, it's only of academic interest anyway.

i have slovakian lines. in the past 10 years i have bred 27 litters. i usually have at least a couple pups per litter that have longer coats, but are not true long coats, as they do have undercoats. in my opinion, a long coat is only a problem when you have no weather proof undercoat and when hair is so long and silky that mats are a constant concern despite daily grooming.

While coats are something of a burden to breeders, I consider them a blessing to the pet owner since they represent an opportunity to own at a reasonable price the very highest quality most beautiful pets.